Project Euler每帖一题（001）

引用

题目：If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23.

Find the sum of all the multiples of 3 or 5 below 1000.

我的python解：

num_3 = 999 / 3
num_5 = 999 / 5
num_15 = 999 / 15
num = 0
for i in range(num_3):
    num += (i+1) * 3
for j in range(num_5):
    num += (j+1) * 5
for x in range(num_15):
    num -= (x+1) * 15
    
print num

如果有更好的的解法，求交流~